Integrand size = 17, antiderivative size = 258 \[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=-\frac {6 a x \left (a+b x^2\right )}{5 b^{3/2} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}}+\frac {2 x \sqrt {a x+b x^3}}{5 b}+\frac {6 a^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 b^{7/4} \sqrt {a x+b x^3}}-\frac {3 a^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{5 b^{7/4} \sqrt {a x+b x^3}} \]
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Time = 0.14 (sec) , antiderivative size = 258, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.353, Rules used = {2049, 2057, 335, 311, 226, 1210} \[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=-\frac {3 a^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right ),\frac {1}{2}\right )}{5 b^{7/4} \sqrt {a x+b x^3}}+\frac {6 a^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 b^{7/4} \sqrt {a x+b x^3}}-\frac {6 a x \left (a+b x^2\right )}{5 b^{3/2} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}}+\frac {2 x \sqrt {a x+b x^3}}{5 b} \]
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Rule 226
Rule 311
Rule 335
Rule 1210
Rule 2049
Rule 2057
Rubi steps \begin{align*} \text {integral}& = \frac {2 x \sqrt {a x+b x^3}}{5 b}-\frac {(3 a) \int \frac {x}{\sqrt {a x+b x^3}} \, dx}{5 b} \\ & = \frac {2 x \sqrt {a x+b x^3}}{5 b}-\frac {\left (3 a \sqrt {x} \sqrt {a+b x^2}\right ) \int \frac {\sqrt {x}}{\sqrt {a+b x^2}} \, dx}{5 b \sqrt {a x+b x^3}} \\ & = \frac {2 x \sqrt {a x+b x^3}}{5 b}-\frac {\left (6 a \sqrt {x} \sqrt {a+b x^2}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 b \sqrt {a x+b x^3}} \\ & = \frac {2 x \sqrt {a x+b x^3}}{5 b}-\frac {\left (6 a^{3/2} \sqrt {x} \sqrt {a+b x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 b^{3/2} \sqrt {a x+b x^3}}+\frac {\left (6 a^{3/2} \sqrt {x} \sqrt {a+b x^2}\right ) \text {Subst}\left (\int \frac {1-\frac {\sqrt {b} x^2}{\sqrt {a}}}{\sqrt {a+b x^4}} \, dx,x,\sqrt {x}\right )}{5 b^{3/2} \sqrt {a x+b x^3}} \\ & = -\frac {6 a x \left (a+b x^2\right )}{5 b^{3/2} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {a x+b x^3}}+\frac {2 x \sqrt {a x+b x^3}}{5 b}+\frac {6 a^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 b^{7/4} \sqrt {a x+b x^3}}-\frac {3 a^{5/4} \sqrt {x} \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{5 b^{7/4} \sqrt {a x+b x^3}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.03 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.26 \[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=\frac {2 x^2 \left (a+b x^2-a \sqrt {1+\frac {b x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3}{4},\frac {7}{4},-\frac {b x^2}{a}\right )\right )}{5 b \sqrt {x \left (a+b x^2\right )}} \]
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Time = 2.27 (sec) , antiderivative size = 178, normalized size of antiderivative = 0.69
method | result | size |
default | \(\frac {2 x \sqrt {b \,x^{3}+a x}}{5 b}-\frac {3 a \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}+\frac {\sqrt {-a b}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}\right )}{5 b^{2} \sqrt {b \,x^{3}+a x}}\) | \(178\) |
elliptic | \(\frac {2 x \sqrt {b \,x^{3}+a x}}{5 b}-\frac {3 a \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}+\frac {\sqrt {-a b}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}\right )}{5 b^{2} \sqrt {b \,x^{3}+a x}}\) | \(178\) |
risch | \(\frac {2 x^{2} \left (b \,x^{2}+a \right )}{5 b \sqrt {x \left (b \,x^{2}+a \right )}}-\frac {3 a \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, E\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}+\frac {\sqrt {-a b}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b}\right )}{5 b^{2} \sqrt {b \,x^{3}+a x}}\) | \(187\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.09 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.17 \[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=\frac {2 \, {\left (\sqrt {b x^{3} + a x} b x + 3 \, a \sqrt {b} {\rm weierstrassZeta}\left (-\frac {4 \, a}{b}, 0, {\rm weierstrassPInverse}\left (-\frac {4 \, a}{b}, 0, x\right )\right )\right )}}{5 \, b^{2}} \]
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\[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=\int \frac {x^{3}}{\sqrt {x \left (a + b x^{2}\right )}}\, dx \]
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\[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=\int { \frac {x^{3}}{\sqrt {b x^{3} + a x}} \,d x } \]
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\[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=\int { \frac {x^{3}}{\sqrt {b x^{3} + a x}} \,d x } \]
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Timed out. \[ \int \frac {x^3}{\sqrt {a x+b x^3}} \, dx=\int \frac {x^3}{\sqrt {b\,x^3+a\,x}} \,d x \]
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